Revision 2

Accepted · core change · record

Changes against revision 1:

Title: Where does 1/f noise stop at low frequency?
Plain: If the 1/f law held down to zero frequency, the total noise power would grow without limit. No measurement has found where the law stops.
Precise · changed · core: Revision 1: The integral of a $1/f$ spectrum diverges logarithmically at both ends, so a physical system needs a lower cutoff $f_{\min}$, set in the fluctuator picture by the longest relaxation time $\tau_{\max} \sim \tau_0 \operatorname{exp}(E_{\max}/T)$. Measurements over many decades have not found a flattening. Determine $f_{\min}$ in a specific well-characterized system (metal film or SQUID) and relate it to the fluctuator distribution.; Revision 2: The integral of a $1/f$ spectrum diverges logarithmically at both ends, so a physical system needs a lower cutoff $f_{\min}$, set in the fluctuator picture by the longest relaxation time $\tau_{\max} \sim \tau_0 \exp(E_{\max}/T)$. Measurements over many decades have not found a flattening. Determine $f_{\min}$ in a specific well-characterized system (metal film or SQUID) and relate it to the fluctuator distribution.
Settled by: Long, drift-controlled noise records on a stable device showing a flattening of S(f), compared with an independently measured distribution of fluctuator relaxation times.
Kind: well-posed
Answer type: value
References: (empty)
Literature status: open
Status note: (empty)
Posed since: (empty)

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