Why Hall angle and resistivity follow different temperature laws

In plain words

In cuprates the resistance grows linearly with temperature while the Hall angle, the deflection of current by a magnetic field, behaves as if a second scattering rate grows as temperature squared.

Precise statement

In optimally doped cuprates $\rho_{xx} \sim T$ while $\cot(\theta_{H}) = \rho_{xx}/\rho_{xy} \sim A + B T^{2}$ over a wide range. Determine whether this requires two distinct relaxation rates (transport and Hall) or follows from a single anisotropic scattering rate on a Fermi surface with hot and cold regions. An answer is a model that reproduces both laws and their doping dependence with one parameter set.

What would settle it

Angle-dependent magnetoresistance mapping of the momentum-resolved scattering rate, fed into a Boltzmann or non-quasiparticle calculation that yields both $\rho_{xx}(T)$ and $\operatorname{cot}(\theta_{H})(T)$.

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