Atomic radius bounded independently of nuclear charge · revision history
Revision 1
Superseded · first revision · record
- Title
- Atomic radius bounded independently of nuclear charge
- Plain
- Heavy atoms are about the same size as light ones, roughly 1e-8 cm across. Prove from the many-electron Schrodinger equation that the size of a neutral atom does not grow with Z.
- Precise
- For a neutral ground state $\psi$ of $H_{Z,Z}$ with one-electron density $\rho$, define $R(Z)$ as the radius with $\int_{|x|>R(Z)}\rho(x)\,dx=1$. Prove $c a_0\le R(Z)\le C a_0$ with $a_0=\hbar^2/(m e^2)$ and constants c, C independent of Z, or show R(Z) grows or shrinks without bound.
- Settled by
- Z-independent upper and lower bounds on R(Z) for the neutral many-body ground state.
- Kind
- well-posed
- Answer type
- proof
- References
- (empty)
- Literature status
- open
- Status note
- Proved in Hartree-Fock theory (Solovej 2003); open for the Schrodinger Hamiltonian.
- Posed since
- (empty)